Biology  by Bradford
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5.4 Non-Mendelian Genetics: revision map

The subtopic in the middle and four tasks round it: label a diagram, complete a table and fill 9 gaps. Every box rests on a learning objective of the topic in the AP Biology course and exam description. Type into the blanks and check them, or print it on A4, Letter or A3 with an answer key.

Unit 5 practice questionsThe whole Unit 5 map

Topic 5.4

Non-Mendelian Genetics

AP Biology · Unit 5 HeredityName

5.4.APatterns that depart from Mendel

PatternWhat happensExample
heterozygote is intermediatered × white snapdragon gives pink
both alleles are fully expressedAB blood type
Sex linkagethe gene is on the X chromosome, so males show a recessive allele more oftenred-green color blindness
Polygenicmany genes add up to one trait, with a continuous rangeheight, skin color
Epistasisone gene masks the effect of anothercoat color in Labrador retrievers
Pleiotropyone gene affects several traitssickle cell allele
Cytoplasmicorganelle DNA is passed on by the mother's eggmitochondrial and chloroplast genes

5.4.AGenes on one chromosome

Two genes close together on the same chromosome are and tend to be inherited together, so a cross does not give the 9 : 3 : 3 : 1 ratio. Crossing over can separate them, and the further apart two genes are, the more often it does. Recombination frequency, the percent of offspring that are recombinants, is therefore a measure of distance: 1% is one map unit. A gene on the X chromosome shows up more often in males, who have only one X.

Topic 5.4Non-Mendelian Genetics

5.4.AIncomplete dominance

,,,,,,1 : 2 : 1in the offspring1234
  1. 1
  2. 2
  3. 3
  4. 4

5.4.ATesting a ratio

A chi-square test compares the observed counts with the counts expected from a hypothesis. For a 3 : 1 cross with 400 offspring (290 dominant, 110 recessive), the expected counts are 300 and 100. χ² = Σ(o − e)²/e = 100/300 + 100/100 = . With one degree of freedom, 1 for two phenotypes, the critical value at p = 0.05 is 3.84, so the result is significant and we fail to reject the hypothesis that the cross gives a 3 : 1 ratio.

Word bank 1.33CodominanceheterozygoteIncomplete dominanceincomplete dominancelinkednotred homozygotewhite homozygote

Answer key

Every box on the sheet with its gaps filled in, as the subtopic reads in full.
  1. LabelIncomplete dominance

    1. red homozygote
    2. heterozygote
    3. white homozygote
    4. incomplete dominance
  2. TablePatterns that depart from Mendel

    PatternWhat happensExample
    Incomplete dominanceheterozygote is intermediatered × white snapdragon gives pink
    Codominanceboth alleles are fully expressedAB blood type
    Sex linkagethe gene is on the X chromosome, so males show a recessive allele more oftenred-green color blindness
    Polygenicmany genes add up to one trait, with a continuous rangeheight, skin color
    Epistasisone gene masks the effect of anothercoat color in Labrador retrievers
    Pleiotropyone gene affects several traitssickle cell allele
    Cytoplasmicorganelle DNA is passed on by the mother's eggmitochondrial and chloroplast genes
  3. GapsGenes on one chromosome

    Two genes close together on the same chromosome are linked and tend to be inherited together, so a cross does not give the 9 : 3 : 3 : 1 ratio. Crossing over can separate them, and the further apart two genes are, the more often it does. Recombination frequency, the percent of offspring that are recombinants, is therefore a measure of distance: 1% is one map unit. A gene on the X chromosome shows up more often in males, who have only one X.

  4. GapsTesting a ratio

    A chi-square test compares the observed counts with the counts expected from a hypothesis. For a 3 : 1 cross with 400 offspring (290 dominant, 110 recessive), the expected counts are 300 and 100. χ² = Σ(o − e)²/e = 100/300 + 100/100 = 1.33. With one degree of freedom, 1 for two phenotypes, the critical value at p = 0.05 is 3.84, so the result is not significant and we fail to reject the hypothesis that the cross gives a 3 : 1 ratio.