A1.2 Nucleic acids. Practice questions with markscheme.
72 original IB-style questions on A1.2, written from the 2025 guide: 30 multiple-choice, 26 short-answer, 8 data-based, 4 drawing, 3 extended-response parts, 1 labelling. Below are two ready-made practice papers built from them, one at standard level (20 marks) and one at higher level (20 marks); switch between them above the paper. Hand one out as a class quiz or homework, or sit it yourself and mark against the scheme. Print it, project it, or build a fresh one on the same topic.
What the guide asks for
10 statements at SL and HL, 5 additional higher level.
- A1.2.1SL / HL DNA as the genetic material of all living organisms
- A1.2.2SL / HL Components of a nucleotide
- A1.2.3SL / HL Sugar–phosphate bonding and the sugar–phosphate “backbone” of DNA and RNA
- A1.2.4SL / HL Bases in each nucleic acid that form the basis of a code
- A1.2.5SL / HL RNA as a polymer formed by condensation of nucleotide monomers
- A1.2.6SL / HL DNA as a double helix made of two antiparallel strands of nucleotides with two strands linked by hydrogen bonding between complementary base pairs
- A1.2.7SL / HL Differences between DNA and RNA
- A1.2.8SL / HL Role of complementary base pairing in allowing genetic information to be replicated and expressed
- A1.2.9SL / HL Diversity of possible DNA base sequences and the limitless capacity of DNA for storing information
- A1.2.10SL / HL Conservation of the genetic code across all life forms as evidence of universal common ancestry
- A1.2.11HL Directionality of RNA and DNA
- A1.2.12HL Purine-to-pyrimidine bonding as a component of DNA helix stability
- A1.2.13HL Structure of a nucleosome
- A1.2.14HL Evidence from the Hershey–Chase experiment for DNA as the genetic material
- A1.2.15HL Chargaff’s data on the relative amounts of pyrimidine and purine bases across diverse life forms
In the bank for A1.2
- 30 multiple-choice
- 26 short-answer
- 8 data-based
- 4 drawing
- 3 extended-response parts
- 1 labelling
- 27 higher level only
Every question is original and tagged to a guide statement. See the whole bank →
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The practice paper
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The diagram shows a section of a DNA molecule containing two base pairs. Explain how the diagram shows that the two strands are antiparallel, and how the two strands are held together.
State the roles of DNA and of RNA in cells.
Compare the nitrogenous bases found in a molecule of DNA with those found in a molecule of RNA.
In any double-stranded DNA molecule, the amount of adenine equals the amount of thymine. Explain why.
Draw and label a diagram of a single DNA nucleotide.
The base composition of the genomes of four viruses was determined by chemical analysis. The results are shown as percentages of the four bases.
| Virus | Adenine / % | Thymine / % | Guanine / % | Cytosine / % |
|---|---|---|---|---|
| P | 30 | 30 | 20 | 20 |
| Q | 35 | 24 | 19 | 22 |
| R | 21 | 21 | 29 | 29 |
| S | 28 | 16 | 34 | 22 |
Original practice questions © Biology by Bradford · CC BY-NC-SA 4.0 · Not affiliated with or endorsed by the International Baccalaureate Organization.
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One mark per point; / separates alternative wording within a point, OR separates alternative answers, words in brackets are not required, underlined words are essential. OWTTE = or words to that effect.
- each backbone is built of alternating phosphates (circles) and sugars (pentagons), so each strand has a direction set by the order of these groups;
- the right-hand strand is drawn inverted relative to the left, so its sugars and phosphates run in the opposite order down the molecule;
- the strand ends are therefore labelled 5′ and 3′ at opposite ends of the molecule / one strand runs 5′ to 3′ downwards while the other runs 3′ to 5′ downwards;
- the strands are joined by hydrogen bonds (dashed lines) between bases on opposite strands;
- the pairing is complementary: cytosine with guanine and thymine with adenine, as shown;
- hydrogen bonds are individually weak, so the strands can be separated, but together they hold the double helix stably, OWTTE;
Accept 'the two strands run in opposite directions' for the second point if the candidate refers to the diagram. Students are not required to state the numbers of hydrogen bonds (A1.2.6), so accept any number of dashed lines per pair.
- DNA is the genetic material / stores hereditary information (in all cells);
- RNA carries/transfers information for protein synthesis (mRNA) / has roles in expressing genes (tRNA/rRNA), OWTTE;
- both contain adenine, guanine and cytosine;
- DNA contains thymine, whereas RNA contains uracil in its place;
- in both, adenine pairs with its complementary pyrimidine (thymine in DNA, uracil in RNA) and guanine pairs with cytosine;
- the two strands are complementary;
- every A on one strand pairs with a T on the other (by hydrogen bonding);
- (so) A and T occur in equal numbers (and likewise G and C), OWTTE;
- pentose sugar (shown as a pentagon) labelled deoxyribose/sugar;
- phosphate (group) attached to the sugar, labelled;
- (nitrogenous) base attached to the sugar (on a different corner from the phosphate), labelled;
Phosphate and base must be attached to the sugar, not to each other. Accept circle for phosphate and rectangle for base.
- (a) [1]
- P and R;
- (b) [2]
- 48 000 base pairs = 96 000 bases;
- 20 % of 96 000 = 19 200 (guanine bases);
Award [2] for 19 200 with or without working. Award [1] for 9 600 (20 % of 48 000).
- (c) [2]
- DNA;
- (all four) genomes contain thymine, which occurs only in DNA / RNA would contain uracil in place of thymine, OWTTE;
- (d) [2 max]
- genetic information is carried by the sequence/order of the bases, not by their proportions;
- the same percentages of A, T, G and C can be arranged in an enormous number of different sequences;
- (so) the genomes can contain different genes / code for different proteins, OWTTE;
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The table shows the meaning of five mRNA codons in the standard genetic code used by most organisms and in three genetic systems whose codes differ slightly from it: human mitochondria, bacteria of the genus Mycoplasma and the nucleus of the ciliate Tetrahymena. In each of the three, no more than four of the 64 codons have a meaning different from the standard code. Which conclusion is best supported by these data?
| Codon | Most organisms | Human mitochondria | Mycoplasma | Tetrahymena nucleus |
|---|---|---|---|---|
| UUU | phenylalanine | phenylalanine | phenylalanine | phenylalanine |
| GGC | glycine | glycine | glycine | glycine |
| AUA | isoleucine | methionine | isoleucine | isoleucine |
| UGA | stop | tryptophan | tryptophan | stop |
| UAA | stop | stop | stop | glutamine |
- All four codes descend from one ancestral code, with a few codons reassigned later
- The differences show that the genetic code is still changing rapidly in most organisms
- The code arose separately in each group, since no two of the four codes are identical
- Because the code varies, it cannot be used as evidence for a common ancestor of life
Which row correctly compares DNA and RNA?
| Row | Sugar in DNA | Sugar in RNA | Base found only in RNA |
|---|---|---|---|
| A. | ribose | deoxyribose | thymine |
| B. | deoxyribose | ribose | uracil |
| C. | deoxyribose | ribose | thymine |
| D. | ribose | deoxyribose | uracil |
- Row B
- Row D
- Row A
- Row C
A DNA synthesizer makes a single strand of DNA with a chosen base sequence, one nucleotide at a time. The first nucleotide is attached to a bead by the 3′ carbon of its sugar, and each new nucleotide is joined to the free 5′ end of the growing strand. In what order does the machine add the nucleotides to make the strand 5′-TCAGGA-3′?
- T, C, A, G, G, A
- A, G, G, A, C, T
- A, G, T, C, C, T
- T, C, C, T, G, A
Proteins are built from 20 different amino acids, and the base sequence of DNA specifies the amino acid at each position. If every amino acid must have its own unique sequence of bases, what is the smallest number of consecutive bases that could code for one amino acid?
- 1
- 2
- 3
- 4
What is a nucleosome?
- A loop of prokaryotic DNA attached to the plasma membrane
- The region of a chromosome where spindle fibres attach
- A ribosome bound to messenger RNA
- DNA wrapped around a core of eight histone proteins
The table describes DNA in a human cell at three levels of organisation, from a single base pair to the whole nucleus.
| Level | Description |
|---|---|
| Base pair | Every base pair joins a purine, a base with two rings, to a pyrimidine, a base with one ring. |
| Nucleosome | Nucleosomes form along almost the whole length of every DNA molecule, on stretches of DNA with very different base sequences. |
| Nucleus | The DNA in one nucleus is about 2 m long in total; the nucleus is about 6 µm across. |
Outline how nucleotides are linked together to form a single strand of DNA.
The diagram shows a model of a nucleotide made from three joined shapes, numbered 1 to 3, with a second nucleotide joined below it to show the start of a polynucleotide strand. Identify the components labelled 1, 2 and 3.
Explain how the structure of DNA is related to its function as the genetic material.
Original practice questions © Biology by Bradford · CC BY-NC-SA 4.0 · Not affiliated with or endorsed by the International Baccalaureate Organization.
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Markscheme BbB-EAECAAAAABQAw-lq
One mark per point; / separates alternative wording within a point, OR separates alternative answers, words in brackets are not required, underlined words are essential. OWTTE = or words to that effect.
- A: almost every codon (such as UUU and GGC) has the same meaning in all four systems, which is best explained by one shared origin; the few differences are single codons reassigned later in particular lineages, so the near-universal code remains evidence of common ancestry;
- A: DNA has deoxyribose and thymine; RNA has ribose and uracil;
- B: the bead holds the nucleotide at the 3′ end (A) and each later nucleotide joins the 5′ end, so the strand is built from its 3′ end to its 5′ end, the reverse of the order in which a cell adds nucleotides; A is the order a cell would use (5′ to 3′), and B and D list complementary bases, which would make a different strand;
- C: DNA has four bases, so one base gives 4 combinations and two give 4² = 16, too few for 20 amino acids, whereas three give 4³ = 64, which is enough;
- D: nucleosome = DNA wound around an octamer of histones (with an H1 linker histone), packaging DNA in eukaryotes;
- (a) [3 max]
- a purine paired with a pyrimidine gives every base pair the same length / A–T and C–G pairs are equally long;
- (so) the double helix has the same width / three-dimensional shape along its whole length, whatever the base sequence;
- the bases lie inside the helix, with the sugar–phosphate backbones on the outside;
- the backbone is the same repeating chain of sugars and phosphates whatever the base sequence;
- histone proteins bind to the outside of the helix / to the backbone rather than to the bases, so their binding does not depend on the base sequence, OWTTE;
- (so) any stretch of DNA can be wound around a core of histones in the same way, OWTTE;
Award marks for links between levels; restating the table gains no mark. Accept attraction between negatively charged phosphate groups and positively charged amino acids of the histones for the fifth point.
- (b) [3 max]
- the DNA is far longer than the nucleus is wide / over 300 000 times as long, so it must be packed tightly to fit;
- wrapping the DNA around histone cores shortens it, and chains of nucleosomes can be coiled further / supercoiled;
- a stretch that could not form nucleosomes would stay unpacked / loose, so it could tangle or fail to fit, OWTTE;
- a further histone attached to the linker DNA holds the DNA in place / links nucleosomes into a compact, stable chain;
Beyond this subtopic. Award if given; the marks above can be earned without it.
- D2.2 packing and unpacking nucleosomes controls which genes are accessible for transcription / helps regulate gene expression, OWTTE;
- D2.1 (further condensation into) chromosomes lets the DNA be separated during mitosis without tangling;
- (condensation reactions form) covalent bonds between nucleotides;
- the phosphate (group) of one nucleotide bonds to the sugar/pentose of the next;
- forming a (continuous) sugar–phosphate backbone (with bases projecting from it);
Accept phosphodiester bond. Do not accept hydrogen bonds.
- 1: phosphate (group);
- 2: pentose sugar (deoxyribose, if DNA);
- 3: nitrogenous base;
- the base sequence stores/encodes (genetic) information;
- (any) sequence and length are possible, giving unlimited capacity/diversity;
- complementary base pairing (A–T, G–C) allows each strand to act as a template;
- (so) DNA can be replicated accurately (and information passed on);
- hydrogen bonds between strands are (individually) weak, so the strands can be separated (for replication/transcription);
- the covalent sugar–phosphate backbone makes the molecule stable, protecting the information;
More in Theme A · Unity and diversity
- A1.1 Water 65
- A2.1 Origins of cells 69
- A2.2 Cell structure 69
- A2.3 Viruses 67
- A3.1 Diversity of organisms 69
- A3.2 Classification and cladistics 66
- A4.1 Evolution and speciation 67
- A4.2 Conservation of biodiversity 65
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