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IB Biology 2025 · Theme B · Form and function

B4.2 Ecological niches. Practice questions with markscheme.

67 original IB-style questions on B4.2, written from the 2025 guide: 31 multiple-choice, 24 short-answer, 8 data-based, 2 extended-response parts, 1 drawing, 1 labelling. This subtopic has no additional higher level content, so the 21-mark practice paper below serves SL and HL alike. Hand one out as a class quiz or homework, or sit it yourself and mark against the scheme. Print it, project it, or build a fresh one on the same topic.

What the guide asks for

13 statements at SL and HL.

  1. B4.2.1SL / HL Ecological niche as the role of a species in an ecosystem
  2. B4.2.2SL / HL Differences between organisms that are obligate anaerobes, facultative anaerobes and obligate aerobes
  3. B4.2.3SL / HL Photosynthesis as the mode of nutrition in plants, algae and several groups of photosynthetic prokaryotes
  4. B4.2.4SL / HL Holozoic nutrition in animals
  5. B4.2.5SL / HL Mixotrophic nutrition in some protists
  6. B4.2.6SL / HL Saprotrophic nutrition in some fungi and bacteria
  7. B4.2.7SL / HL Diversity of nutrition in archaea
  8. B4.2.8SL / HL Relationship between dentition and the diet of omnivorous and herbivorous representative members of the family
  9. B4.2.9SL / HL Adaptations of herbivores for feeding on plants and of plants for resisting herbivory
  10. B4.2.10SL / HL Adaptations of predators for finding, catching and killing prey and of prey animals for resisting predation
  11. B4.2.11SL / HL Adaptations of plant form for harvesting light
  12. B4.2.12SL / HL Fundamental and realized niches
  13. B4.2.13SL / HL Competitive exclusion and the uniqueness of ecological niches

In the bank for B4.2

  • 31 multiple-choice
  • 24 short-answer
  • 8 data-based
  • 2 extended-response parts
  • 1 drawing
  • 1 labelling
  • 0 higher level only

Every question is original and tagged to a guide statement. See the whole bank →

Make your own

The practice paper

No additional higher level content in this subtopic, so one paper serves both · 21 marks
Take it online → Build a fresh paper Paper code BbB-EAAAAAQAABQAOrfA
Biology · topic quiz
Standard level · topic practice, not an exam format
30 minutes21 marks

Paper code: this paper was generated, so the code is its recipe. Enter it at biologybybradford.com/exam-maker to rebuild this exact paper and its markscheme.

Covers B4.2 Ecological niches · SL
Name:
1.

Caterpillars of two moth species, V and W, were reared either on leaves of a plant variety that produces a toxic alkaloid or on leaves of a variety that produces none. The activity of a detoxifying enzyme in the gut of each species was also measured.

Which conclusion is best supported by the data?

[1]
SpeciesSurvival on alkaloid-free leaves / %Survival on leaves with alkaloid / %Gut detoxifying enzyme activity / arbitrary units
V888542
W90123
  1. The alkaloid is a physical defence that stops both species biting the leaves
  2. The alkaloid gives the plant equal protection against both moth species
  3. Species W survives on leaves with alkaloid by avoiding eating the leaves
  4. Species V has a metabolic adaptation for feeding on the defended plant
2.

Two species of flatworm, P and Q, live in upland streams, where the water gets warmer with distance downstream. The table shows the temperature ranges in which each species was found.

Which statement is supported by the data?

[1]
SituationTemperature range / °C
P kept alone in the laboratory (survives and breeds)6–23
P in streams where Q is absent6–22
P in streams where Q is present6–13
Q in streams where P is present13–24
  1. Where Q is absent, the realized niche of P is larger than its fundamental niche
  2. The fundamental niche of P is 6–13 °C, the range it occupies alongside Q
  3. Where Q is present, the realized niche of P is narrower than its fundamental niche
  4. P is absent above 13 °C where Q lives because it cannot tolerate warm water
3.

A species of archaea is grown in the dark, in air, in a medium that contains carbon dioxide and hydrogen sulfide but no other carbon compounds. It produces ATP and grows. What is the source of energy for its ATP production?

[1]
  1. Oxidation of an inorganic chemical taken up from its surroundings
  2. Oxidation of carbon compounds in other cells that it has engulfed
  3. Absorption of light energy by pigments located in its cell membrane
  4. Oxidation of carbon compounds absorbed from its growth medium
4.

The diagram compares the upper jaws of two hominids, drawn to the same scale. Which inference about the diet of Homo sapiens is best supported by the diagram?

[1]
Paranthropus robustusHomo sapiensincisorscaninespremolarsmolarsupper jaws viewed from below, to the same scale
  1. It ate a mixed diet that needed less heavy grinding than that of Paranthropus
  2. It ate only soft fruit, as it had no premolars or molars for chewing food
  3. It ate only meat, sliced by long bladed teeth like the carnassials of a cat
  4. It ate mainly hard seeds and tough roots that needed prolonged heavy grinding
5.

The figure shows the percentage of full sunlight reaching different heights in a tropical rainforest. A strangler fig seed dropped by a bird may lodge on a branch at X, where it grows as an epiphyte before sending roots down to the soil. A seed that falls to Y germinates on the forest floor. What is the advantage of germinating at X rather than at Y?

[1]
0 10 20 30 40 Height above forest floor / m X Y 100 60 30 12 6 4 2.5 1.5 Light reaching each height / % of full sunlight sunlight X: seed lodged on a branch Y: seed on the forest floor
  1. It receives more light than the leaves at the very top of the canopy trees do
  2. It gets about twenty times as much light as at Y without first building a trunk
  3. It gets only slightly more light than at Y, as most light passes the canopy
  4. Its roots reach soil water and mineral ions sooner than those of a seedling at Y
6.

Prey animals have chemical, physical and behavioural adaptations that help them resist predation. Outline adaptations of prey animals for resisting predation, including at least one example of each type.

[4]
7.

An invasive plant is introduced into a habitat where its niche strongly overlaps that of a native plant. Predict the possible outcomes for the two species, using the competitive exclusion principle and the idea of the fundamental and realized niche.

[4]
8.

Mud from the bottom of a pond was mixed with shredded paper, packed into a glass cylinder to a depth of 10 cm and covered with 5 cm of pond water. When the cylinder was set up, the mud had been stirred with the water and contained oxygen at every depth. The cylinder was sealed and kept beside a window for eight weeks. Algae and cyanobacteria in the water photosynthesized in the light, releasing oxygen. The oxygen concentration was then measured at different depths with a fine probe; the diagram shows the cylinder and the results. Three kinds of microbe, S, T and U, were isolated from the mud. S and T are saprotrophs that feed on the paper. Each microbe was grown in the laboratory in a nutrient medium bubbled either with air or with nitrogen gas. The table shows the results and the layers of the cylinder in which each microbe was found.

MicrobeGrowth in medium bubbled with airGrowth in medium bubbled with nitrogenLayers of the cylinder in which it was found
Sgoodnone2 only
Tgoodmoderate2 and 3
Unonegood3 only
water light mud mixed with shredded paper 1 2 3 0 2 4 6 8 10 0 5 10 15 oxygen concentration / mg dm⁻³ depth below water surface / cm
(a)Explain the distribution of each of the three microbes in the cylinder, in terms of how oxygen affects its cells.[3]
(b)Explain how the activity of the saprotrophs S and T in the mud created the oxygen-free habitat in which U now lives.[3]
(c)The cylinder was then moved to a dark cupboard for four weeks. Predict, with reasons, how the distribution of U in the cylinder would change.[2]

Original practice questions © Biology by Bradford · CC BY-NC-SA 4.0 · Not affiliated with or endorsed by the International Baccalaureate Organization.
Rebuild or edit this exact paper (and its markscheme): biologybybradford.com/exam-maker?code=BbB-EAAAAAQAABQAOrfA

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Markscheme BbB-EAAAAAQAABQAOrfA

One mark per point; / separates alternative wording within a point, OR separates alternative answers, words in brackets are not required, underlined words are essential. OWTTE = or words to that effect.

1. B4.2.9 [1]
  • D: V survives almost as well with the alkaloid (85 %) as without it (88 %) and has high detoxifying enzyme activity, so it can detoxify the plant's secondary compound; the alkaloid is a chemical, not a physical, defence (A), it kills most W but few V (B), and W survives poorly on these leaves (C);
2. B4.2.12 [1]
  • C: alone in the laboratory P tolerates 6–23 °C, its fundamental niche, but where Q is present it occupies only 6–13 °C, so competition restricts its realized niche; 6–13 °C is the realized niche (A), P tolerates up to 23 °C when Q is absent (B), and 6–22 °C lies within 6–23 °C, as a realized niche cannot exceed the fundamental niche (C);
3. B4.2.7 [1]
  • A: archaea use light, oxidation of inorganic chemicals or oxidation of carbon compounds for ATP production; in the dark light cannot be the source (not B), and the medium holds no carbon compounds other than carbon dioxide, which cannot be oxidized further, and no other cells to engulf (not C or D), so this species must be oxidizing an inorganic chemical such as hydrogen sulfide;
4. B4.2.8 [1]
  • A: the premolars and molars of *Homo sapiens* are much smaller than those of *Paranthropus*, so its food needed less heavy grinding, consistent with an omnivorous diet; prolonged heavy grinding of hard, tough plant food fits *Paranthropus* (B); the diagram shows no bladed carnassial teeth (C); and it shows premolars and molars (D);
5. B4.2.11 [1]
  • B: about 30 % of full sunlight reaches 25 m but only about 1.5 % reaches the forest floor, so the seedling at X starts with about 20 times as much light (30 ÷ 1.5) without investing in a self-supporting trunk; a seedling at X is further from the soil (A), the canopy top receives 100 % (C), and the canopy absorbs most of the light, so the difference is large (D);
6. B4.2.10 [4 max]
  • chemical: production of toxins / venom / distasteful chemicals, e.g. poison dart frogs with toxic skin, skunks spraying repellent;
  • chemical adaptations are often combined with warning coloration (aposematism) so predators learn to avoid the prey, OWTTE;
  • physical: hard shells / spines / armour, e.g. tortoise shell, porcupine quills, hedgehog spines;
  • physical: camouflage / cryptic coloration or shape, e.g. stick insects, flatfish matching the sea floor;
  • physical: mimicry of a harmful species by a harmless one, e.g. hoverflies resembling wasps;
  • behavioural: fleeing / rapid escape, living in herds or shoals (dilution effect, more eyes for vigilance), e.g. zebra, sardines;
  • behavioural: freezing / playing dead / being active only at night / alarm calls to warn others, OWTTE;

Mark the first three types only where a candidate gives many examples of one type; full marks require at least one chemical, one physical and one behavioural adaptation. Accept any correct named example.

7. B4.2.13 [4 max]
  • if the niches overlap almost completely and the invader is the superior competitor, the native species may be outcompeted and locally excluded/driven to extinction;
  • if the overlap is only partial, the two may undergo niche partitioning/differentiation, with the native restricted to a smaller realized niche where the invader competes less;
  • the invader may expand into any resources the native was not fully using;
  • the outcome depends on the degree of niche overlap and the relative competitive abilities (and on predators/disease acting on either species), OWTTE;

Predict a range of outcomes with reasoning; use of niche terminology expected.

8. B4.2.1-B4.2.2
  • (a) [3 max]
    • S is an obligate aerobe: it cannot grow without oxygen, so it is confined to layer 2, the only part of the mud that contains oxygen;
    • T is a facultative anaerobe: it grows with or without oxygen, so it can live both in layer 2 and in the oxygen-free mud of layer 3;
    • U is an obligate anaerobe: it cannot grow where oxygen is present / oxygen is toxic to it, so it is found only in layer 3, where the oxygen concentration is zero;
    • the oxygen concentration at each depth is an abiotic factor that sets the limits of where each microbe can live / is part of the niche of each, OWTTE;

    Each of the first three marks needs both the oxygen-tolerance group and a link to the oxygen concentration of the layer(s) where the microbe is found. Do not accept 'U prefers no oxygen'.

  • (b) [3 max]
    • S and T secrete digestive enzymes onto the paper and absorb the products of this external digestion / feed by saprotrophic nutrition;
    • they use the carbon compounds they absorb in aerobic respiration, which uses up oxygen;
    • oxygen reaches the mud only by diffusing slowly down from the water (through the waterlogged mud);
    • so below about 1 cm into the mud (6 cm below the water surface) oxygen is used faster than it is replaced, and its concentration falls to zero;
    • the feeding of one group of organisms has changed an abiotic factor, creating conditions inside the fundamental niche of U (and outside that of S), OWTTE;

    Content pivot. Accept 'decomposers' for saprotrophs.

  • (c) [2 max]
    • U would be found closer to the mud surface / in the upper mud (layer 2) as well as in layer 3, as the oxygen-free zone extends upwards;
    • in darkness the algae and cyanobacteria cannot photosynthesize, so they release no oxygen (and they use oxygen in respiration);
    • the saprotrophs go on using oxygen, so the oxygen still in the water and upper mud is used up and is not replaced, OWTTE;

    The prediction alone does not earn both marks; a reason linked to the loss of photosynthesis is required.

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